Todd West
03/06/2024 · Primary School
Solve each of the following equations. Homework Help \( \begin{array}{ll}\text { a. } 2 x+8=3 x-4 & \text { b. } 1.5 w+3=3+2 w \\ \text { c. } 48+8 x+23=7 & \text { d. } 6 x-21=5 x+17+x\end{array} \)
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Step-by-step Solution
Solve the equation \( 2x+8=3x-4 \).
Solve the equation by following steps:
- step0: Solve for \(x\):
\(2x+8=3x-4\)
- step1: Move the variable to the left side:
\(2x+8-3x=-4\)
- step2: Subtract the terms:
\(-x+8=-4\)
- step3: Move the constant to the right side:
\(-x=-4-8\)
- step4: Subtract the numbers:
\(-x=-12\)
- step5: Change the signs:
\(x=12\)
Solve the equation \( 1.5w+3=3+2w \).
Solve the equation by following steps:
- step0: Solve for \(w\):
\(1.5w+3=3+2w\)
- step1: Cancel equal terms:
\(1.5w=2w\)
- step2: Add or subtract both sides:
\(1.5w-2w=0\)
- step3: Subtract the terms:
\(-0.5w=0\)
- step4: Change the signs:
\(0.5w=0\)
- step5: Rewrite the expression:
\(w=0\)
Solve the equation \( 48+8x+23=7 \).
Solve the equation by following steps:
- step0: Solve for \(x\):
\(48+8x+23=7\)
- step1: Add the numbers:
\(71+8x=7\)
- step2: Move the constant to the right side:
\(8x=7-71\)
- step3: Subtract the numbers:
\(8x=-64\)
- step4: Divide both sides:
\(\frac{8x}{8}=\frac{-64}{8}\)
- step5: Divide the numbers:
\(x=-8\)
Solve the equation \( 6x-21=5x+17+x \).
Solve the equation by following steps:
- step0: Solve for \(x\):
\(6x-21=5x+17+x\)
- step1: Add the terms:
\(6x-21=6x+17\)
- step2: Cancel equal terms:
\(-21=17\)
- step3: The statement is false:
\(x \in \varnothing \)
a. The solution to the equation \(2x+8=3x-4\) is \(x=12\).
b. The solution to the equation \(1.5w+3=3+2w\) is \(w=0\).
c. The solution to the equation \(48+8x+23=7\) is \(x=-8\).
d. The equation \(6x-21=5x+17+x\) has no solution.
Quick Answer
a. \(x=12\)
b. \(w=0\)
c. \(x=-8\)
d. No solution
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