Todd West
03/06/2024 · Primary School

Solve each of the following equations. Homework Help \( \begin{array}{ll}\text { a. } 2 x+8=3 x-4 & \text { b. } 1.5 w+3=3+2 w \\ \text { c. } 48+8 x+23=7 & \text { d. } 6 x-21=5 x+17+x\end{array} \)

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Solve the equation \( 2x+8=3x-4 \). Solve the equation by following steps: - step0: Solve for \(x\): \(2x+8=3x-4\) - step1: Move the variable to the left side: \(2x+8-3x=-4\) - step2: Subtract the terms: \(-x+8=-4\) - step3: Move the constant to the right side: \(-x=-4-8\) - step4: Subtract the numbers: \(-x=-12\) - step5: Change the signs: \(x=12\) Solve the equation \( 1.5w+3=3+2w \). Solve the equation by following steps: - step0: Solve for \(w\): \(1.5w+3=3+2w\) - step1: Cancel equal terms: \(1.5w=2w\) - step2: Add or subtract both sides: \(1.5w-2w=0\) - step3: Subtract the terms: \(-0.5w=0\) - step4: Change the signs: \(0.5w=0\) - step5: Rewrite the expression: \(w=0\) Solve the equation \( 48+8x+23=7 \). Solve the equation by following steps: - step0: Solve for \(x\): \(48+8x+23=7\) - step1: Add the numbers: \(71+8x=7\) - step2: Move the constant to the right side: \(8x=7-71\) - step3: Subtract the numbers: \(8x=-64\) - step4: Divide both sides: \(\frac{8x}{8}=\frac{-64}{8}\) - step5: Divide the numbers: \(x=-8\) Solve the equation \( 6x-21=5x+17+x \). Solve the equation by following steps: - step0: Solve for \(x\): \(6x-21=5x+17+x\) - step1: Add the terms: \(6x-21=6x+17\) - step2: Cancel equal terms: \(-21=17\) - step3: The statement is false: \(x \in \varnothing \) a. The solution to the equation \(2x+8=3x-4\) is \(x=12\). b. The solution to the equation \(1.5w+3=3+2w\) is \(w=0\). c. The solution to the equation \(48+8x+23=7\) is \(x=-8\). d. The equation \(6x-21=5x+17+x\) has no solution.

Quick Answer

a. \(x=12\) b. \(w=0\) c. \(x=-8\) d. No solution
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