Cook Johnson
01/19/2023 · Primary School

Divide. \[ \frac{-15 x^{5}+30 x^{4}-40}{5 x^{2}} \]

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To divide the expression \[ \frac{-15 x^{5}+30 x^{4}-40}{5 x^{2}}, \] we can separate the terms in the numerator and divide each by the denominator \(5 x^{2}\): \[ \frac{-15 x^{5}}{5 x^{2}} + \frac{30 x^{4}}{5 x^{2}} - \frac{40}{5 x^{2}}. \] Now, we simplify each term: 1. For the first term: \[ \frac{-15 x^{5}}{5 x^{2}} = -3 x^{3} \quad \text{(since } -15 \div 5 = -3 \text{ and } x^{5} \div x^{2} = x^{3}\text{)} \] 2. For the second term: \[ \frac{30 x^{4}}{5 x^{2}} = 6 x^{2} \quad \text{(since } 30 \div 5 = 6 \text{ and } x^{4} \div x^{2} = x^{2}\text{)} \] 3. For the third term: \[ \frac{-40}{5 x^{2}} = -\frac{8}{x^{2}} \quad \text{(since } -40 \div 5 = -8\text{)} \] Putting it all together, we have: \[ -3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}. \] Thus, the final result is: \[ \boxed{-3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}}. \]

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\[ -3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}. \]
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