Cook Johnson
01/19/2023 · Primary School
Divide. \[ \frac{-15 x^{5}+30 x^{4}-40}{5 x^{2}} \]
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Tutor-Verified Answer
Step-by-step Solution
To divide the expression
\[
\frac{-15 x^{5}+30 x^{4}-40}{5 x^{2}},
\]
we can separate the terms in the numerator and divide each by the denominator \(5 x^{2}\):
\[
\frac{-15 x^{5}}{5 x^{2}} + \frac{30 x^{4}}{5 x^{2}} - \frac{40}{5 x^{2}}.
\]
Now, we simplify each term:
1. For the first term:
\[
\frac{-15 x^{5}}{5 x^{2}} = -3 x^{3} \quad \text{(since } -15 \div 5 = -3 \text{ and } x^{5} \div x^{2} = x^{3}\text{)}
\]
2. For the second term:
\[
\frac{30 x^{4}}{5 x^{2}} = 6 x^{2} \quad \text{(since } 30 \div 5 = 6 \text{ and } x^{4} \div x^{2} = x^{2}\text{)}
\]
3. For the third term:
\[
\frac{-40}{5 x^{2}} = -\frac{8}{x^{2}} \quad \text{(since } -40 \div 5 = -8\text{)}
\]
Putting it all together, we have:
\[
-3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}.
\]
Thus, the final result is:
\[
\boxed{-3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}}.
\]
Quick Answer
\[
-3 x^{3} + 6 x^{2} - \frac{8}{x^{2}}.
\]
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