Daniel Wyatt
07/02/2024 · High School

En la operación combinada \( \begin{array}{ll}160-\{8+[7 X 4-(56 \div 2)+15 X 3+ \\ (200-95)]\} & \text { el resultado es }\end{array} \)

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Para resolver la operación combinada \( 160 - \{ 8 + [7 \times 4 - (56 \div 2) + 15 \times 3 + (200 - 95)] \} \), vamos a seguir el orden de las operaciones (paréntesis, exponentes, multiplicación y división de izquierda a derecha, y finalmente suma y resta de izquierda a derecha). 1. **Resolver los paréntesis internos**: - \( 56 \div 2 = 28 \) - \( 200 - 95 = 105 \) Ahora sustituimos estos resultados en la expresión: \[ 160 - \{ 8 + [7 \times 4 - 28 + 15 \times 3 + 105] \} \] 2. **Realizar las multiplicaciones**: - \( 7 \times 4 = 28 \) - \( 15 \times 3 = 45 \) Sustituyendo estos resultados: \[ 160 - \{ 8 + [28 - 28 + 45 + 105] \} \] 3. **Resolver dentro de los corchetes**: - \( 28 - 28 = 0 \) - \( 0 + 45 = 45 \) - \( 45 + 105 = 150 \) Ahora la expresión se simplifica a: \[ 160 - \{ 8 + 150 \} \] 4. **Sumar dentro de los corchetes**: - \( 8 + 150 = 158 \) Ahora la expresión es: \[ 160 - 158 \] 5. **Realizar la resta final**: - \( 160 - 158 = 2 \) Por lo tanto, el resultado de la operación combinada es: \[ \boxed{2} \]

Quick Answer

El resultado de la operación es 2.
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