\[ \text { Surface Area of Cylinder }=2 \pi r h+2 \pi r^{2} \] Where \( r \) is the radius of the cylinder and \( h \) is the height of the cylinder. Find the surface area when \( r \) is 8 inches and \( h \) is 8 inches. A. \( 160 \pi \mathrm{in}^{2} \) B. \( 154 \pi \mathrm{in}^{2} \) C. \( 256 \pi \mathrm{in}^{2} \) D. \( 288 \pi \mathrm{in}^{2} \)

To find the surface area of the cylinder, we can use the formula: \[ \text{Surface Area of Cylinder} = 2 \pi r h + 2 \pi r^2 \] Given that \( r = 8 \) inches and \( h = 8 \) inches, we can substitute these values into the formula. First, calculate the lateral surface area \( 2 \pi r h \): \[ 2 \pi r h = 2 \pi (8)(8) = 2 \pi (64) = 128 \pi \] Next, calculate the area of the two circular bases \( 2 \pi r^2 \): \[ 2 \pi r^2 = 2 \pi (8^2) = 2 \pi (64) = 128 \pi \] Now, add both areas together to find the total surface area: \[ \text{Total Surface Area} = 128 \pi + 128 \pi = 256 \pi \] Thus, the surface area of the cylinder is: \[ \boxed{256 \pi \, \text{in}^2} \] The correct answer is C. \( 256 \pi \mathrm{in}^{2} \).