Vega Hodgson
06/06/2023 · Middle School
(b) (1) For each point in the diagram below, draw the reflection of the point about the \( x \)-axis and indicate the coordinates of the image. (2) Rewrite and complete the following: \( \mathrm{A}(-3 ; 4) \rightarrow \mathrm{A}^{\prime}( \); ) \( \mathrm{B}(-5 ; 2) \rightarrow \mathrm{B}^{\prime}(~ ; ~) \) \( \mathrm{C}(0 ; 3) \rightarrow \mathrm{C}( \); ) \( \mathrm{D}(6 ;-2) \rightarrow \mathrm{D}( \); ) \( \mathrm{E}(2 ;-5) \rightarrow \mathrm{E}^{\prime}(~ ;) \) (3) What do you notice? (4) Write down, in words, a rule for reflecti) Conclusion
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(1) To draw the reflection of a point about the \( x \)-axis, you need to keep the \( x \)-coordinate the same and change the sign of the \( y \)-coordinate. Here are the reflections and their coordinates:
- \( \mathrm{A}(-3 ; 4) \rightarrow \mathrm{A}^{\prime}(-3 ; -4) \)
- \( \mathrm{B}(-5 ; 2) \rightarrow \mathrm{B}^{\prime}(-5 ; -2) \)
- \( \mathrm{C}(0 ; 3) \rightarrow \mathrm{C}^{\prime}(0 ; -3) \)
- \( \mathrm{D}(6 ; -2) \rightarrow \mathrm{D}^{\prime}(6 ; 2) \)
- \( \mathrm{E}(2 ; -5) \rightarrow \mathrm{E}^{\prime}(2 ; 5) \)
(2) The completed table is as follows:
\( \mathrm{A}(-3 ; 4) \rightarrow \mathrm{A}^{\prime}(-3 ; -4) \)
\( \mathrm{B}(-5 ; 2) \rightarrow \mathrm{B}^{\prime}(-5 ; -2) \)
\( \mathrm{C}(0 ; 3) \rightarrow \mathrm{C}^{\prime}(0 ; -3) \)
\( \mathrm{D}(6 ; -2) \rightarrow \mathrm{D}^{\prime}(6 ; 2) \)
\( \mathrm{E}(2 ; -5) \rightarrow \mathrm{E}^{\prime}(2 ; 5) \)
(3) Upon observing the reflections, you notice that the \( x \)-coordinates remain the same, while the \( y \)-coordinates are negated (i.e., their signs are reversed).
(4) The rule for reflecting a point about the \( x \)-axis is: to find the image of a point \( (x, y) \), keep the \( x \)-coordinate the same and change the sign of the \( y \)-coordinate to \( -y \).
Quick Answer
To reflect a point about the \( x \)-axis, keep the \( x \)-coordinate the same and change the \( y \)-coordinate to its opposite. For example, \( \mathrm{A}(-3 ; 4) \) becomes \( \mathrm{A}^{\prime}(-3 ; -4) \). The rule is: \( (x, y) \rightarrow (x, -y) \).
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