Jimenez Summers
10/13/2023 · Primary School
c) \( \left\{\begin{array}{l}\sqrt{6+x}-3 \sqrt{3 y+4}=-10 \\ 4 \sqrt{3 y+4}-5 \sqrt{6+x}=6\end{array}\right. \)
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Tutor-Verified Answer
Step-by-step Solution
Решим систему уравнений:
\[
\left\{
\begin{array}{l}
\sqrt{6+x}-3 \sqrt{3y+4}=-10 \quad (1) \\
4 \sqrt{3y+4}-5 \sqrt{6+x}=6 \quad (2)
\end{array}
\right.
\]
Начнем с первого уравнения (1):
\[
\sqrt{6+x} - 3\sqrt{3y+4} = -10
\]
Переносим \(3\sqrt{3y+4}\) на правую сторону:
\[
\sqrt{6+x} = 3\sqrt{3y+4} - 10
\]
Теперь возведем обе стороны в квадрат:
\[
6+x = (3\sqrt{3y+4} - 10)^2
\]
Раскроем скобки:
\[
6+x = 9(3y+4) - 60\sqrt{3y+4} + 100
\]
Упрощаем:
\[
6+x = 27y + 36 - 60\sqrt{3y+4} + 100
\]
\[
6+x = 27y + 136 - 60\sqrt{3y+4}
\]
Теперь выразим \(x\):
\[
x = 27y + 130 - 60\sqrt{3y+4} \quad (3)
\]
Теперь подставим (3) во второе уравнение (2):
\[
4\sqrt{3y+4} - 5\sqrt{6+x} = 6
\]
Подставим \(\sqrt{6+x}\) из (1):
\[
4\sqrt{3y+4} - 5(-10 + 3\sqrt{3y+4}) = 6
\]
Упрощаем:
\[
4\sqrt{3y+4} + 50 - 15\sqrt{3y+4} = 6
\]
Соберем подобные:
\[
(4 - 15)\sqrt{3y+4} + 50 = 6
\]
\[
-11\sqrt{3y+4} + 50 = 6
\]
Переносим 50 на правую сторону:
\[
-11\sqrt{3y+4} = 6 - 50
\]
\[
-11\sqrt{3y+4} = -44
\]
Делим обе стороны на -11:
\[
\sqrt{3y+4} = 4
\]
Теперь возведем в квадрат:
\[
3y + 4 = 16
\]
\[
3y = 12
\]
\[
y = 4
\]
Теперь подставим значение \(y\) в (3) для нахождения \(x\):
\[
x = 27(4) + 130 - 60\sqrt{3(4)+4}
\]
Сначала найдем \(\sqrt{3(4)+4}\):
\[
\sqrt{12 + 4} = \sqrt{16} = 4
\]
Теперь подставим:
\[
x = 108 + 130 - 60(4)
\]
\[
x = 238 - 240
\]
\[
x = -2
\]
Таким образом, решение системы:
\[
\boxed{(x, y) = (-2, 4)}
\]
Quick Answer
Решение системы уравнений: \(x = -2\), \(y = 4\).
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