Bradley Carroll
11/03/2023 · Middle School
1 De un triángulo sabemos que: \( \mathrm{a}=6 \mathrm{~m}, \mathrm{~B}=45^{\circ} \) y \( \mathrm{C}=105^{\circ} \). Calcula los restantes elementos.
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Para resolver el triángulo dado, utilizaremos la ley de los senos y la suma de los ángulos de un triángulo.
1. **Encontrar el ángulo A**:
Sabemos que la suma de los ángulos de un triángulo es \(180^\circ\). Por lo tanto, podemos calcular el ángulo A:
\[
A = 180^\circ - B - C = 180^\circ - 45^\circ - 105^\circ = 30^\circ
\]
2. **Encontrar el lado b**:
Usamos la ley de los senos, que establece que:
\[
\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}
\]
Primero, calculamos \(b\):
\[
\frac{a}{\sin A} = \frac{b}{\sin B}
\]
Sustituyendo los valores que tenemos:
\[
\frac{6 \, \text{m}}{\sin(30^\circ)} = \frac{b}{\sin(45^\circ)}
\]
Sabemos que \(\sin(30^\circ) = 0.5\) y \(\sin(45^\circ) = \frac{\sqrt{2}}{2}\):
\[
\frac{6 \, \text{m}}{0.5} = \frac{b}{\frac{\sqrt{2}}{2}}
\]
Simplificando:
\[
12 \, \text{m} = \frac{b}{\frac{\sqrt{2}}{2}}
\]
Multiplicamos ambos lados por \(\frac{\sqrt{2}}{2}\):
\[
b = 12 \, \text{m} \cdot \frac{\sqrt{2}}{2} = 6\sqrt{2} \, \text{m} \approx 8.49 \, \text{m}
\]
3. **Encontrar el lado c**:
Ahora calculamos \(c\) usando la ley de los senos nuevamente:
\[
\frac{a}{\sin A} = \frac{c}{\sin C}
\]
Sustituyendo los valores:
\[
\frac{6 \, \text{m}}{\sin(30^\circ)} = \frac{c}{\sin(105^\circ)}
\]
Sabemos que \(\sin(105^\circ) = \sin(180^\circ - 75^\circ) = \sin(75^\circ) = \frac{\sqrt{6} + \sqrt{2}}{4}\):
\[
\frac{6 \, \text{m}}{0.5} = \frac{c}{\frac{\sqrt{6} + \sqrt{2}}{4}}
\]
Simplificando:
\[
12 \, \text{m} = \frac{c}{\frac{\sqrt{6} + \sqrt{2}}{4}}
\]
Multiplicamos ambos lados por \(\frac{\sqrt{6} + \sqrt{2}}{4}\):
\[
c = 12 \, \text{m} \cdot \frac{\sqrt{6} + \sqrt{2}}{4} = 3(\sqrt{6} + \sqrt{2}) \, \text{m} \approx 10.39 \, \text{m}
\]
4. **Resumen de los elementos del triángulo**:
- \(A = 30^\circ\)
- \(B = 45^\circ\)
- \(C = 105^\circ\)
- \(a = 6 \, \text{m}\)
- \(b \approx 8.49 \, \text{m}\)
- \(c \approx 10.39 \, \text{m}\)
Por lo tanto, los elementos restantes del triángulo son:
- \(A = 30^\circ\)
- \(b \approx 8.49 \, \text{m}\)
- \(c \approx 10.39 \, \text{m}\)
Quick Answer
- \(A = 30^\circ\)
- \(b \approx 8.49 \, \text{m}\)
- \(c \approx 10.39 \, \text{m}\)
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