Acrop with a rootzone depth of 1.0 m is to be grown in a sandy sol. Determine the sol moisture h8ding capacity given that Field capacity \( =33 \% \) Wilting point \( =23 \% \) Doy sal density \( =1123.3 \mathrm{~kg} \mathrm{~m}^{3} \) Deusity of water \( =100 \mathrm{~kg} \mathrm{M}_{-3} \)

To determine the soil moisture holding capacity, we need to calculate the difference between the field capacity and the wilting point, and then convert that to a volume of water per unit area of soil. 1. **Calculate the available water capacity (AWC)**: \[ \text{AWC} = \text{Field Capacity} - \text{Wilting Point} \] Given: - Field Capacity = 33% = 0.33 (as a decimal) - Wilting Point = 23% = 0.23 (as a decimal) \[ \text{AWC} = 0.33 - 0.23 = 0.10 \text{ (or 10%)} \] 2. **Convert AWC to volume of water per unit area**: The AWC represents the volume of water that can be held in the soil per unit volume of soil. To find the volume of water that can be held in a root zone depth of 1.0 m, we can use the following formula: \[ \text{Volume of water} = \text{AWC} \times \text{Depth} \times \text{Bulk Density} \] Where: - Depth = 1.0 m - Bulk Density = 1123.3 kg/m³ First, we need to convert the AWC from a percentage to a volume in m³ of water per m³ of soil: \[ \text{Volume of water} = 0.10 \times 1.0 \, \text{m} \times 1123.3 \, \text{kg/m}^3 \] Since the density of water is 1000 kg/m³, we can convert the mass of water to volume: \[ \text{Volume of water} = 0.10 \times 1.0 \, \text{m} \times 1123.3 \, \text{kg/m}^3 \times \frac{1 \, \text{m}^3}{1000 \, \text{kg}} = 0.11233 \, \text{m}^3 \] 3. **Final Result**: The soil moisture holding capacity for the root zone depth of 1.0 m in the sandy soil is approximately **0.11233 m³ of water per m² of soil**. This means that for every square meter of soil, the available water capacity is about 112.33 liters.