The probabilities of four events are shown. List them in order from least $$ t $$ greatest. $$ \frac{6}{13} \quad 3 \text { out of } 9 $$

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$$ \frac{1}{3}, \frac{6}{13} $$ To compare the probabilities, we need to express them in a common format, typically as decimals or fractions. 1. The first probability is $$ \frac{6}{13} $$. 2. The second probability is $$ 3 \text{ out of } 9 $$, which can be expressed as a fraction: $$ \frac{3}{9} = \frac{1}{3} $$ Now, we will convert both probabilities to decimal form for easier comparison: 1. For $$ \frac{6}{13} $$: $$ \frac{6}{13} \approx 0.4615 $$ 2. For $$ \frac{1}{3} $$: $$ \frac{1}{3} \approx 0.3333 $$ Now we can compare the two decimal values: - $$ 0.3333 $$ (which is $$ \frac{1}{3} $$) is less than $$ 0.4615 $$ (which is $$ \frac{6}{13} $$). Thus, in order from least to greatest, the probabilities are: $$ \frac{1}{3} \quad \text{and} \quad \frac{6}{13} $$ So the final answer is: $$ \frac{1}{3}, \frac{6}{13} $$

The probabilities of four events are shown. List them in order from least \( t \) greatest. \[ \frac{6}{13} \quad 3 \text { out of } 9 \]

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The probabilities of four events are shown. List them in order from least \( t \) greatest. \[ \frac{6}{13} \quad 3 \text { out of } 9 \]

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