Johnson Mitchell
04/26/2024 · Junior High School
\( ( x ) = x + 3 \quad g ( x ) = \frac { x ^ { 2 } + 5 x + 6 } { x + 2 } \)
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It looks like you've provided two functions, \( f(x) \) and \( g(x) \). However, the function \( f(x) \) seems to be incomplete. I will assume you meant to write:
\[
f(x) = x + 3
\]
and
\[
g(x) = \frac{x^2 + 5x + 6}{x + 2}
\]
Let's simplify \( g(x) \):
1. Factor the numerator \( x^2 + 5x + 6 \):
\[
x^2 + 5x + 6 = (x + 2)(x + 3)
\]
2. Substitute this back into \( g(x) \):
\[
g(x) = \frac{(x + 2)(x + 3)}{x + 2}
\]
3. For \( x \neq -2 \), we can simplify:
\[
g(x) = x + 3
\]
Thus, for \( x \neq -2 \), we have:
\[
g(x) = x + 3
\]
Now, we can see that both functions \( f(x) \) and \( g(x) \) are equal for all \( x \) except \( x = -2 \):
\[
f(x) = g(x) \quad \text{for } x \neq -2
\]
If you have any specific questions or further operations you'd like to perform with these functions, please let me know!
Quick Answer
\( f(x) = g(x) = x + 3 \) for \( x \neq -2 \)
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