$$ \left[\begin{array}{ll}x & 7 y \ z & 4\end{array} ight]=\left[\begin{array}{cc}16 & 28 \ 13 & 4\end{array} ight] $$ $$ x=16 $$ (Simplify your answer.) $$ y=\square $$ (Simplify your answer.)

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$$ \left[\begin{array}{ll}x & 7 y \ z & 4\end{array}ight]=\left[\begin{array}{cc}16 & 28 \ 13 & 4\end{array}ight] $$ $$ x=16 $$ (Simplify your answer.) $$ y=\square $$ (Simplify your answer.)

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$$ y = 4 $$. To solve for $$ y $$ in the matrix equation $$ \left[\begin{array}{ll}x & 7y \ z & 4\end{array}\right]=\left[\begin{array}{cc}16 & 28 \ 13 & 4\end{array}\right], $$ we can equate the corresponding elements of the matrices. From the first row and first column, we have: $$ x = 16. $$ From the first row and second column, we have: $$ 7y = 28. $$ To find $$ y $$, we can solve the equation $$ 7y = 28 $$: $$ y = \frac{28}{7} = 4. $$ Thus, the simplified answers are: $$ x = 16, $$ $$ y = 4. $$ So, the final answer is: $$ y = 4 $$.

\( \left[\begin{array}{ll}x & 7 y \\ z & 4\end{array}\right]=\left[\begin{array}{cc}16 & 28 \\ 13 & 4\end{array}\right] \) \( x=16 \) (Simplify your answer.) \( y=\square \) (Simplify your answer.)

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\( \left[\begin{array}{ll}x & 7 y \\ z & 4\end{array}\right]=\left[\begin{array}{cc}16 & 28 \\ 13 & 4\end{array}\right] \) \( x=16 \) (Simplify your answer.) \( y=\square \) (Simplify your answer.)

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