Solve the system of linear inequalities by graphing. \( \begin{array}{l}2 x+y>8 \\ 2 x+y<-1\end{array} \)

Consider the following quadratic function. \[ g(x)=-3 x^{2}-18 x-25 \]

59. \( \frac{1 x}{2}+2=x+4 \) 61. \( x \cdot \frac{3 x}{4}=\frac{x}{7}+3 \) 63. \( \frac{9 x}{4} \cdot 6=\frac{2 x}{3}+\frac{1}{3} \) 65. \( \frac{3 x}{5} \cdot 7=\frac{2 x}{6}+1 \) 67. \( \frac{x}{3}+x=10+\frac{2 x}{9} \) 69. \( \frac{x}{5}+\frac{x}{2}=x \cdot 3 \)

2. ถ้า \( \sum_{i=1}^{10}\left(3 x^{2}-x+5\right)=170 \) และ \( \sum_{i=1}^{10} x^{2}=80 \) แล้ว \( \bar{x} \) มีค่าตรงกับข้อใด \( \begin{array}{llll}\text { ก. } 10 & \text { ข. } 20 & \text { ค. } 30 & \text { ง. } 40\end{array} \)

Find the sum of the first 4 terns in the sequence \( x_{n}=\{7,11,15,19\} \)

\[ \text { ME VS LEBRON } \] So the other day I was minding my own business when a famous ball player introduced himself to me. You know his name. Anyways, he said that he always wanted to meet me. I agreed with him and went on my way to help the needy as I usually do when I am off work. He grabbed me quickly and challenged me to a shooting contest (basketball, not guns). To get him off my back, I agreed. We were to shoot 18 three pointers. We bet \( \$ 1 \) on the first shot, \( \$ 2 \) on the second, \( \$ 4 \) on the third, \( \$ 8 \) on the forth...so forth and so forth as we doubled each time. Lebron beat me on the first 17 shots, and I won the last shot. Who came ahead on this game and by how much?