Murphy Whittaker
09/04/2023 · Elementary School

Obtener la distancia entre los siguientes pontos 1.- \( A\left(\frac{5}{2}, 3\right) \quad B(-4,-2) \)

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Para calcular la distancia entre los puntos \( A\left(\frac{5}{2}, 3\right) \) y \( B(-4, -2) \), utilizamos la fórmula de la distancia entre dos puntos en el plano cartesiano: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Donde \( (x_1, y_1) \) son las coordenadas del punto \( A \) y \( (x_2, y_2) \) son las coordenadas del punto \( B \). Sustituyendo los valores: - \( x_1 = \frac{5}{2} \) - \( y_1 = 3 \) - \( x_2 = -4 \) - \( y_2 = -2 \) Ahora, calculamos la distancia: \[ d = \sqrt{\left(-4 - \frac{5}{2}\right)^2 + \left(-2 - 3\right)^2} \] Primero, calculamos \( -4 - \frac{5}{2} \): \[ -4 = -\frac{8}{2} \quad \Rightarrow \quad -4 - \frac{5}{2} = -\frac{8}{2} - \frac{5}{2} = -\frac{13}{2} \] Ahora, calculamos \( -2 - 3 \): \[ -2 - 3 = -5 \] Sustituyendo estos resultados en la fórmula de la distancia: \[ d = \sqrt{\left(-\frac{13}{2}\right)^2 + (-5)^2} \] Calculamos los cuadrados: \[ \left(-\frac{13}{2}\right)^2 = \frac{169}{4} \quad \text{y} \quad (-5)^2 = 25 \] Ahora, convertimos \( 25 \) a cuartas partes para poder sumar: \[ 25 = \frac{100}{4} \] Sumamos los dos términos: \[ d = \sqrt{\frac{169}{4} + \frac{100}{4}} = \sqrt{\frac{269}{4}} = \frac{\sqrt{269}}{2} \] Por lo tanto, la distancia entre los puntos \( A \) y \( B \) es: \[ d = \frac{\sqrt{269}}{2} \]

Quick Answer

La distancia entre los puntos \( A\left(\frac{5}{2}, 3\right) \) y \( B(-4, -2) \) es \( \frac{\sqrt{269}}{2} \).
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