Todd Zimmerman
04/10/2024 · Elementary School
\begin{tabular}{|l|}\hline 2.- Calcular: \( [f(x)-g(x)] \) o \( h(x) \) \\ SI \( f(x)=(6 x+4)^{2} \) \\ \( g(x)=40 x^{2}+20 x-12 \) \\ \( h(x)=2 x-3 \)\end{tabular}
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Para resolver el problema, primero calculamos \( f(x) - g(x) \) y luego evaluamos \( h(x) \). Vamos paso a paso:
1. Calculamos \( f(x) - g(x) \):
\[ f(x) = (6x + 4)^2 \]
\[ g(x) = 40x^2 + 20x - 12 \]
\[ f(x) - g(x) = (6x + 4)^2 - (40x^2 + 20x - 12) \]
Para expandir \( (6x + 4)^2 \), utilizamos la fórmula del cuadrado de una suma:
\[ (a + b)^2 = a^2 + 2ab + b^2 \]
Donde \( a = 6x \) y \( b = 4 \):
\[ (6x + 4)^2 = (6x)^2 + 2 \cdot 6x \cdot 4 + 4^2 \]
\[ = 36x^2 + 48x + 16 \]
Ahora sustituimos en la expresión de \( f(x) - g(x) \):
\[ f(x) - g(x) = (36x^2 + 48x + 16) - (40x^2 + 20x - 12) \]
\[ = 36x^2 + 48x + 16 - 40x^2 - 20x + 12 \]
\[ = -4x^2 + 28x + 28 \]
2. Evaluamos \( h(x) \):
\[ h(x) = 2x - 3 \]
Por lo tanto, la expresión final es:
\[ [f(x) - g(x)] \text{ o } h(x) = (-4x^2 + 28x + 28) \text{ o } (2x - 3) \]
Quick Answer
\[ [f(x) - g(x)] \text{ o } h(x) = (-4x^2 + 28x + 28) \text{ o } (2x - 3) \]
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