PRACTICE Sketch the graph of each equation. \( \begin{array}{ll}\text { 18. } y=\frac{3}{8} x+5 & \text { 19. } y=-\frac{1}{2}\end{array} \)

To sketch the graphs of the given equations, we will analyze each equation separately. ### 18. \( y = \frac{3}{8}x + 5 \) This is a linear equation in slope-intercept form \( y = mx + b \), where: - \( m = \frac{3}{8} \) (the slope) - \( b = 5 \) (the y-intercept) **Steps to sketch the graph:** 1. **Plot the y-intercept**: Start by plotting the point (0, 5) on the graph. This is where the line crosses the y-axis. 2. **Use the slope**: The slope \( \frac{3}{8} \) means that for every 8 units you move to the right (positive x-direction), you move up 3 units (positive y-direction). - From (0, 5), move 8 units to the right to (8, 5) and then move up 3 units to (8, 8). Plot the point (8, 8). 3. **Draw the line**: Connect the points (0, 5) and (8, 8) with a straight line, extending it in both directions. ### 19. \( y = -\frac{1}{2} \) This equation represents a horizontal line because the value of \( y \) is constant at \( -\frac{1}{2} \) for all values of \( x \). **Steps to sketch the graph:** 1. **Identify the y-value**: The line will be at \( y = -\frac{1}{2} \). 2. **Draw the line**: Draw a horizontal line across the graph at the height of \( -\frac{1}{2} \). This line will extend infinitely in both the left and right directions. ### Summary of the Graphs: - For \( y = \frac{3}{8}x + 5 \), you have a line that rises gently from left to right, crossing the y-axis at (0, 5). - For \( y = -\frac{1}{2} \), you have a horizontal line that runs through the point (0, -0.5). You can now sketch these graphs based on the descriptions provided!