Floyd Christensen
09/25/2023 · Senior High School

b) \( \begin{array}{ll}x=3 & x-y=1 \\ x=5 & x+y=7\end{array} \)

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To solve the system of equations given in the form of pairs, we can analyze each pair separately. 1. **First Pair:** \[ \begin{cases} x = 3 \\ x - y = 1 \end{cases} \] From the first equation, we have \( x = 3 \). We can substitute this value into the second equation: \[ 3 - y = 1 \] Solving for \( y \): \[ -y = 1 - 3 \\ -y = -2 \\ y = 2 \] So, the solution for the first pair is \( (x, y) = (3, 2) \). 2. **Second Pair:** \[ \begin{cases} x = 5 \\ x + y = 7 \end{cases} \] From the first equation, we have \( x = 5 \). We can substitute this value into the second equation: \[ 5 + y = 7 \] Solving for \( y \): \[ y = 7 - 5 \\ y = 2 \] So, the solution for the second pair is \( (x, y) = (5, 2) \). In summary, the solutions for the pairs of equations are: - For the first pair: \( (3, 2) \) - For the second pair: \( (5, 2) \)

Quick Answer

For the first pair: \( (3, 2) \) For the second pair: \( (5, 2) \)
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