What is the largest number that evenly divides the top and bottom of $$ 12 / 20 $$ ? (A) 2

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The largest number that divides $$ 12 / 20 $$ is 4. To find the largest number that evenly divides both the numerator (12) and the denominator (20) of the fraction $$ \frac{12}{20} $$, we need to determine the greatest common divisor (GCD) of 12 and 20. First, we can find the prime factorizations of both numbers: - The prime factorization of 12 is: $$ 12 = 2^2 \times 3^1 $$ - The prime factorization of 20 is: $$ 20 = 2^2 \times 5^1 $$ Next, we identify the common prime factors and their lowest powers: - The common prime factor is $$ 2 $$. - The lowest power of $$ 2 $$ in both factorizations is $$ 2^2 $$. Thus, the GCD of 12 and 20 is: $$ GCD(12, 20) = 2^2 = 4 $$ Therefore, the largest number that evenly divides both the numerator and the denominator of $$ \frac{12}{20} $$ is $$ 4 $$. The answer is $$ \boxed{4} $$.

What is the largest number that evenly divides the top and bottom of \( 12 / 20 \) ? (A) 2

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What is the largest number that evenly divides the top and bottom of \( 12 / 20 \) ? (A) 2

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