Clark Deleon
08/30/2024 · Primary School
b-f \( f(x)=\frac{2 x+1}{3 x+2} \)
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Tutor-Verified Answer
Step-by-step Solution
Para encontrar la función inversa \( f^{-1}(x) \) de la función \( f(x) = \frac{2x + 1}{3x + 2} \), seguimos estos pasos:
1. **Reemplazar \( f(x) \) por \( y \)**:
\[
y = \frac{2x + 1}{3x + 2}
\]
2. **Intercambiar \( x \) y \( y \)**:
\[
x = \frac{2y + 1}{3y + 2}
\]
3. **Resolver para \( y \)**:
Multiplicamos ambos lados por \( 3y + 2 \) para eliminar el denominador:
\[
x(3y + 2) = 2y + 1
\]
Esto se simplifica a:
\[
3xy + 2x = 2y + 1
\]
4. **Reorganizar la ecuación**:
Llevamos todos los términos que contienen \( y \) a un lado y los demás al otro lado:
\[
3xy - 2y = 1 - 2x
\]
5. **Factorizar \( y \)**:
\[
y(3x - 2) = 1 - 2x
\]
6. **Despejar \( y \)**:
\[
y = \frac{1 - 2x}{3x - 2}
\]
Por lo tanto, la función inversa es:
\[
f^{-1}(x) = \frac{1 - 2x}{3x - 2}
\]
Quick Answer
La función inversa de \( f(x) = \frac{2x + 1}{3x + 2} \) es \( f^{-1}(x) = \frac{1 - 2x}{3x - 2} \).
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