If the original sample of Zn had a mass of 1.4 g , what mass of \( \mathrm{ZnCl}_{2} \) can be produced in the reacti \( \square \mathrm{g} \)

To find the mass of \( \mathrm{ZnCl}_{2} \) that can be produced from the given mass of Zn, we need to use the balanced chemical equation for the reaction between Zn and \( \mathrm{ZnCl}_{2} \). The balanced chemical equation for the reaction between Zn and \( \mathrm{ZnCl}_{2} \) is: \[ \mathrm{Zn} + 2\mathrm{HCl} \rightarrow \mathrm{ZnCl}_{2} + \mathrm{H}_{2} \] From the balanced chemical equation, we can see that 1 mole of Zn reacts to produce 1 mole of \( \mathrm{ZnCl}_{2} \). Given that the mass of the original sample of Zn is 1.4 g, we need to convert this mass to moles of Zn using its molar mass. The molar mass of Zn is approximately 65.38 g/mol. Let's calculate the number of moles of Zn in the original sample: \[ \text{Moles of Zn} = \frac{\text{Mass of Zn}}{\text{Molar mass of Zn}} \] Once we have the number of moles of Zn, we can determine the mass of \( \mathrm{ZnCl}_{2} \) that can be produced by multiplying the number of moles of Zn by the molar mass of \( \mathrm{ZnCl}_{2} \). The molar mass of \( \mathrm{ZnCl}_{2} \) is approximately 136.28 g/mol. Let's calculate the mass of \( \mathrm{ZnCl}_{2} \) that can be produced. Calculate the value by following steps: - step0: Calculate: \(\frac{1.4}{65.38}\) - step1: Convert the expressions: \(\frac{\frac{7}{5}}{\frac{3269}{50}}\) - step2: Multiply by the reciprocal: \(\frac{7}{5}\times \frac{50}{3269}\) - step3: Reduce the numbers: \(\frac{10}{467}\) The number of moles of Zn in the original sample is approximately 0.0214 moles. Now, we can calculate the mass of \( \mathrm{ZnCl}_{2} \) that can be produced by multiplying the number of moles of Zn by the molar mass of \( \mathrm{ZnCl}_{2} \): \[ \text{Mass of } \mathrm{ZnCl}_{2} = \text{Moles of Zn} \times \text{Molar mass of } \mathrm{ZnCl}_{2} \] Let's calculate the mass of \( \mathrm{ZnCl}_{2} \) that can be produced. Calculate the value by following steps: - step0: Calculate: \(0.0214\times 136.28\) - step1: Multiply the numbers: \(2.916392\) The mass of \( \mathrm{ZnCl}_{2} \) that can be produced from the original sample of Zn is approximately 2.916 g.