Munoz Allan
05/27/2023 · High School
Exercise 2: (Theory on pages \( 169-170 \) ) 1) Sarah buys a microwave for R2 500 and pays for it using a hire purchase loan. The interest rate is \( 18 \% \) per annum and the loan is to paid back over 2 years. Calculate: a) Sarah's monthly repayments. b) The interest that Sarah pays over 2 years.
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Tutor-Verified Answer
Step-by-step Solution
To calculate Sarah's monthly repayments and the total interest paid over 2 years for her hire purchase loan, we can use the formula for the monthly payment on an installment loan, which is given by:
\[
M = P \frac{r(1 + r)^n}{(1 + r)^n - 1}
\]
Where:
- \( M \) = monthly payment
- \( P \) = principal amount (the loan amount)
- \( r \) = monthly interest rate (annual interest rate divided by 12)
- \( n \) = total number of payments (number of months)
### Given:
- Principal amount \( P = R2,500 \)
- Annual interest rate = \( 18\% \) or \( 0.18 \)
- Monthly interest rate \( r = \frac{0.18}{12} = 0.015 \)
- Loan term = 2 years = \( 2 \times 12 = 24 \) months
### a) Calculate Sarah's monthly repayments:
Substituting the values into the formula:
\[
M = 2500 \frac{0.015(1 + 0.015)^{24}}{(1 + 0.015)^{24} - 1}
\]
Calculating \( (1 + 0.015)^{24} \):
\[
(1 + 0.015)^{24} \approx 1.432364654
\]
Now substituting this back into the formula:
\[
M = 2500 \frac{0.015 \times 1.432364654}{1.432364654 - 1}
\]
Calculating the numerator:
\[
0.015 \times 1.432364654 \approx 0.02148546981
\]
Calculating the denominator:
\[
1.432364654 - 1 \approx 0.432364654
\]
Now substituting these values:
\[
M = 2500 \frac{0.02148546981}{0.432364654} \approx 2500 \times 0.0497 \approx 124.25
\]
So, Sarah's monthly repayments are approximately **R124.25**.
### b) Calculate the total interest that Sarah pays over 2 years:
First, we calculate the total amount paid over the 2 years:
\[
\text{Total amount paid} = M \times n = 124.25 \times 24 \approx 2982
\]
Now, we can find the total interest paid by subtracting the principal from the total amount paid:
\[
\text{Total interest} = \text{Total amount paid} - P = 2982 - 2500 = 482
\]
Thus, the total interest that Sarah pays over 2 years is approximately **R482**.
### Summary:
- a) Sarah's monthly repayments: **R124.25**
- b) Total interest paid over 2 years: **R482**
Quick Answer
Sarah's monthly repayments are approximately R124.25, and the total interest paid over 2 years is approximately R482.
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