Mccarthy Weber
01/15/2023 · Senior High School
Question 1 Multiply and simplify completely, including the elimination of all negative exponents: \( \left(\frac{3 x^{5}}{2 y^{9}}\right)^{5} \cdot\left(\frac{2^{2} y^{6}}{3^{4} x^{-2}}\right) \) Answer:
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To solve the expression
\[
\left(\frac{3 x^{5}}{2 y^{9}}\right)^{5} \cdot\left(\frac{2^{2} y^{6}}{3^{4} x^{-2}}\right),
\]
we will first simplify each part separately.
1. **Simplifying the first part:**
\[
\left(\frac{3 x^{5}}{2 y^{9}}\right)^{5} = \frac{(3)^{5} (x^{5})^{5}}{(2)^{5} (y^{9})^{5}} = \frac{243 x^{25}}{32 y^{45}}.
\]
2. **Simplifying the second part:**
\[
\frac{2^{2} y^{6}}{3^{4} x^{-2}} = \frac{4 y^{6}}{81 x^{-2}} = \frac{4 y^{6} x^{2}}{81}.
\]
3. **Now, we multiply the two simplified parts together:**
\[
\frac{243 x^{25}}{32 y^{45}} \cdot \frac{4 y^{6} x^{2}}{81} = \frac{243 \cdot 4 \cdot x^{25} \cdot x^{2} \cdot y^{6}}{32 \cdot 81 \cdot y^{45}}.
\]
4. **Calculating the constants:**
\[
243 \cdot 4 = 972,
\]
\[
32 \cdot 81 = 2592.
\]
5. **Combining the powers of \(x\) and \(y\):**
\[
x^{25} \cdot x^{2} = x^{27},
\]
\[
\frac{y^{6}}{y^{45}} = y^{6 - 45} = y^{-39}.
\]
6. **Putting it all together:**
\[
\frac{972 x^{27}}{2592 y^{39}}.
\]
7. **Now, we simplify the fraction:**
\[
\frac{972}{2592} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2.6667} = \frac{1}{2
Quick Answer
The simplified expression is \( \frac{972 x^{27}}{2592 y^{39}} \).
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit