Newton Joseph
02/15/2023 · Middle School
16. Calcula el vértice de \( f(x)=2 x^{2}+4 x-1 \) \( \begin{array}{lll}\text { a) }(-3 ;-1) & \text { c) }(1 ; 3) & \text { e) }(-1 ;-3) \\ \text { b) }(1 ;-3) & \text { d) }(2 ;-1) & \end{array} \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Para encontrar el vértice de la función cuadrática \( f(x) = 2x^2 + 4x - 1 \), podemos usar la fórmula del vértice, que se encuentra en la forma estándar de una parábola \( f(x) = ax^2 + bx + c \). El vértice \( (h, k) \) se puede calcular usando las siguientes fórmulas:
\[
h = -\frac{b}{2a}
\]
\[
k = f(h)
\]
En nuestra función, tenemos:
- \( a = 2 \)
- \( b = 4 \)
- \( c = -1 \)
Primero, calculamos \( h \):
\[
h = -\frac{4}{2 \cdot 2} = -\frac{4}{4} = -1
\]
Ahora, sustituimos \( h \) en la función para encontrar \( k \):
\[
k = f(-1) = 2(-1)^2 + 4(-1) - 1
\]
\[
= 2(1) - 4 - 1
\]
\[
= 2 - 4 - 1 = -3
\]
Por lo tanto, el vértice de la función es \( (-1, -3) \).
La respuesta correcta es:
\[
\text{e) } (-1, -3)
\]
Quick Answer
El vértice de la función es (-1, -3).
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