Crawford Whittaker
06/21/2023 · Senior High School
The ratio of an object's weight on Earth to its weight on Neptune is \( 5: 7 \). How much would a person who weighs 150 pounds on Earth weigh on Neptune?
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Step-by-step Solution
To find the weight of a person on Neptune given their weight on Earth and the ratio of weights, we can set up the problem using the given ratio of weights.
Let \( W_E \) be the weight on Earth and \( W_N \) be the weight on Neptune. According to the problem, the ratio of the weight on Earth to the weight on Neptune is given as:
\[
\frac{W_E}{W_N} = \frac{5}{7}
\]
We know that the person's weight on Earth, \( W_E \), is 150 pounds. We can substitute this value into the ratio:
\[
\frac{150}{W_N} = \frac{5}{7}
\]
To solve for \( W_N \), we can cross-multiply:
\[
150 \cdot 7 = 5 \cdot W_N
\]
Calculating the left side:
\[
1050 = 5 \cdot W_N
\]
Now, divide both sides by 5 to isolate \( W_N \):
\[
W_N = \frac{1050}{5} = 210
\]
Thus, the weight of the person on Neptune would be:
\[
\boxed{210} \text{ pounds}
\]
Quick Answer
The person would weigh 210 pounds on Neptune.
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