Which table has a constant of proportionality between $$ y $$ and $$ x $$ of $$ \frac{1}{5} $$ ?

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A table with pairs (0, 0), (5, 1), (10, 2), (15, 3), and (20, 4) has a constant of proportionality of $$ \frac{1}{5} $$ between $$ y $$ and $$ x $$. To find a table that has a constant of proportionality of $$ \frac{1}{5} $$ between $$ y $$ and $$ x $$, we need to look for pairs of $$ (x, y) $$ values that satisfy the relationship $$ y = \frac{1}{5} x $$. Here are some examples of pairs that would fit this relationship: - If $$ x = 0 $$, then $$ y = \frac{1}{5} \cdot 0 = 0 $$ → (0, 0) - If $$ x = 5 $$, then $$ y = \frac{1}{5} \cdot 5 = 1 $$ → (5, 1) - If $$ x = 10 $$, then $$ y = \frac{1}{5} \cdot 10 = 2 $$ → (10, 2) - If $$ x = 15 $$, then $$ y = \frac{1}{5} \cdot 15 = 3 $$ → (15, 3) - If $$ x = 20 $$, then $$ y = \frac{1}{5} \cdot 20 = 4 $$ → (20, 4) So, a table that represents this relationship could look like this: $$ \begin{array}{|c|c|} \hline x & y \ \hline 0 & 0 \ 5 & 1 \ 10 & 2 \ 15 & 3 \ 20 & 4 \ \hline \end{array} $$ In this table, the value of $$ y $$ is always $$ \frac{1}{5} $$ times the value of $$ x $$, confirming that the constant of proportionality is indeed $$ \frac{1}{5} $$.

Which table has a constant of proportionality between \( y \) and \( x \) of \( \frac{1}{5} \) ?

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Which table has a constant of proportionality between \( y \) and \( x \) of \( \frac{1}{5} \) ?

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