Evaluate. Then interpret the result in terms of the area above and/or below the \( x \)-axis, \( \int_{-1}^{1}\left(x^{3}-3 x\right) d x \) 1 \( \int\left(x^{3}-3 x\right) d x=\square \) (Type an integer or a simplified fraction.)

Calculate the integral \( \int_{-1}^{1}(x^3-3x)dx \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int_{-1}^{1} x^{3}-3x dx\) - step1: Evaluate the integral: \(\int x^{3}-3x dx\) - step2: Use properties of integrals: \(\int x^{3} dx-\int 3x dx\) - step3: Evaluate the integral: \(\frac{1}{4}x^{4}-\frac{3}{2}x^{2}\) - step4: Return the limits: \(\left(\frac{1}{4}x^{4}-\frac{3}{2}x^{2}\right)\bigg |_{-1}^{1}\) - step5: Calculate the value: \(0\) The result of the integral \( \int_{-1}^{1}(x^3-3x)dx \) is 0. Interpreting this result in terms of the area above and/or below the \( x \)-axis, the integral represents the net area between the curve \( y = x^3 - 3x \) and the \( x \)-axis from \( x = -1 \) to \( x = 1 \). Since the result is 0, it means that the area above the \( x \)-axis is equal to the area below the \( x \)-axis, resulting in a net area of 0.