Elliott Simpson
07/02/2023 · Junior High School
Identify whether arithmetic, geometric, harmonic or \( 1,3,9,27, \ldots .= \) geometric Fibonacci or general. \( 1,3,5,7 \ldots= \) arithmetic \( 1,3,6,10 \ldots= \) Fibonacci \( 1, \frac{1}{4}, \frac{1}{7}, \frac{1}{10} \ldots= \) Harmonic \( 1,1,2,3,5 \ldots= \)
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Let's analyze the sequences you've provided:
1. **\( 1, 3, 9, 27, \ldots \)**: This is a geometric sequence where each term is multiplied by 3 to get the next term. The common ratio is 3.
2. **\( 1, 3, 5, 7, \ldots \)**: This is an arithmetic sequence where each term increases by 2. The common difference is 2.
3. **\( 1, 3, 6, 10, \ldots \)**: This is a sequence of triangular numbers, which is not a Fibonacci sequence. The nth term can be expressed as \( \frac{n(n+1)}{2} \). So, it is neither Fibonacci nor general.
4. **\( 1, \frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \ldots \)**: This sequence does not fit the standard definitions of harmonic or any other common sequence type. The terms are not in a harmonic progression, as harmonic sequences are defined by the reciprocals of an arithmetic sequence.
5. **\( 1, 1, 2, 3, 5, \ldots \)**: This is the Fibonacci sequence, where each term is the sum of the two preceding terms.
To summarize:
- \( 1, 3, 9, 27, \ldots \) = Geometric
- \( 1, 3, 5, 7, \ldots \) = Arithmetic
- \( 1, 3, 6, 10, \ldots \) = Triangular numbers (not Fibonacci)
- \( 1, \frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \ldots \) = Not a standard sequence type
- \( 1, 1, 2, 3, 5, \ldots \) = Fibonacci
Quick Answer
- \( 1, 3, 9, 27, \ldots \) = Geometric
- \( 1, 3, 5, 7, \ldots \) = Arithmetic
- \( 1, 3, 6, 10, \ldots \) = Triangular numbers
- \( 1, \frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \ldots \) = Not a standard sequence type
- \( 1, 1, 2, 3, 5, \ldots \) = Fibonacci
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