Frazier Wagner
09/19/2023 · Senior High School

\( \left[\begin{array}{ll}3 & 0 \\ 7 & 3\end{array}\right]=\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]+\left[\begin{array}{cc}3 & \text { vet } \\ 0+6\end{array}\right] \)

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It seems like you're trying to express a matrix equation, but there are some inconsistencies in the notation. Let's clarify the components of the equation. You have: \[ \left[\begin{array}{ll}3 & 0 \\ 7 & 3\end{array}\right] = \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] + \left[\begin{array}{cc}3 & \text{vet} \\ 0+6\end{array}\right] \] 1. The left-hand side is a \(2 \times 2\) matrix: \[ \left[\begin{array}{ll}3 & 0 \\ 7 & 3\end{array}\right] \] 2. The first matrix on the right-hand side is also a \(2 \times 2\) matrix: \[ \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] \] 3. The second matrix on the right-hand side seems to have a placeholder "vet" and an expression "0+6" which is not clear. Assuming "vet" is a variable or a placeholder for a number, let's denote it as \(x\). The second matrix would then look like: \[ \left[\begin{array}{cc}3 & x \\ 6\end{array}\right] \] However, this matrix is not properly defined as a \(2 \times 2\) matrix because it has only one element in the second row. To make this a valid equation, we need to ensure that all matrices are of the same dimensions. If we assume that the second matrix should also be a \(2 \times 2\) matrix, it should be something like: \[ \left[\begin{array}{cc}3 & x \\ 6 & y\end{array}\right] \] where \(y\) is another variable. So, the equation could be rewritten as: \[ \left[\begin{array}{ll}3 & 0 \\ 7 & 3\end{array}\right] = \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] + \left[\begin{array}{cc}3 & x \\ 6 & y\end{array}\right] \] Now, we can equate the corresponding elements of the matrices: 1. From the first row, first column: \[ 3 = 0 + 3 \quad \text{(this is true)} \] 2. From the first row, second column: \[ 0 = 1 + x \quad \Rightarrow \quad x = -1 \] 3. From the second row, first column: \[ 7 = 1 + 6 \quad \text{(this is true)} \] 4. From the second row, second column: \[ 3 = 0 + y \quad \Rightarrow \quad y = 3 \] Thus, if we assume the second matrix is: \[ \left[\begin{array}{cc}3 & -1 \\ 6 & 3\end{array}\right] \] then the equation holds true. If you have a specific context or additional information regarding "vet" or the structure of the matrices, please provide that for a more accurate interpretation!

Quick Answer

The equation is true if the second matrix is: \[ \left[\begin{array}{cc}3 & -1 \\ 6 & 3\end{array}\right] \]
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