Pritchard Reed
03/14/2024 · Elementary School

1 Individua per quali valori di \( a \) la seguente uguaglianza è vera: \( (3 a-12)(a-7)(5-a)=0 \)

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Per risolvere l'equazione \( (3a - 12)(a - 7)(5 - a) = 0 \), dobbiamo trovare i valori di \( a \) che rendono ciascun fattore uguale a zero. 1. **Primo fattore**: \( 3a - 12 = 0 \) \[ 3a = 12 \implies a = \frac{12}{3} = 4 \] 2. **Secondo fattore**: \( a - 7 = 0 \) \[ a = 7 \] 3. **Terzo fattore**: \( 5 - a = 0 \) \[ a = 5 \] Quindi, i valori di \( a \) per cui l'uguaglianza è vera sono: \[ a = 4, \quad a = 7, \quad a = 5 \] In sintesi, i valori di \( a \) che soddisfano l'equazione sono \( a = 4, 5, 7 \).

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I valori di \( a \) che soddisfano l'equazione sono \( a = 4, 5, 7 \).
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