Wells Hodges
04/13/2023 · Primary School
Which of the following is an equivalent expression to \( \frac{\left(2^{-3} \cdot 9^{3}\right)^{-4}}{2^{9} \cdot 9^{-10}} \) with only positive exponents, generated by applying the Properties of Integer Exponents? (1 point) \( \frac{2^{3}}{9^{2}} \)
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Tutor-Verified Answer
Step-by-step Solution
To simplify the expression \( \frac{\left(2^{-3} \cdot 9^{3}\right)^{-4}}{2^{9} \cdot 9^{-10}} \), we will apply the properties of integer exponents step by step.
1. **Simplify the numerator**:
\[
\left(2^{-3} \cdot 9^{3}\right)^{-4} = (2^{-3})^{-4} \cdot (9^{3})^{-4}
\]
Using the property \( (a^m)^n = a^{m \cdot n} \):
\[
(2^{-3})^{-4} = 2^{12} \quad \text{and} \quad (9^{3})^{-4} = 9^{-12}
\]
Therefore, the numerator becomes:
\[
2^{12} \cdot 9^{-12}
\]
2. **Combine the numerator and denominator**:
Now we have:
\[
\frac{2^{12} \cdot 9^{-12}}{2^{9} \cdot 9^{-10}}
\]
3. **Separate the fractions**:
We can separate the fractions:
\[
\frac{2^{12}}{2^{9}} \cdot \frac{9^{-12}}{9^{-10}}
\]
4. **Apply the properties of exponents**:
For the first fraction:
\[
\frac{2^{12}}{2^{9}} = 2^{12 - 9} = 2^{3}
\]
For the second fraction:
\[
\frac{9^{-12}}{9^{-10}} = 9^{-12 - (-10)} = 9^{-12 + 10} = 9^{-2}
\]
5. **Combine the results**:
Now we have:
\[
2^{3} \cdot 9^{-2}
\]
6. **Convert to positive exponents**:
To express \( 9^{-2} \) with a positive exponent, we can write:
\[
9^{-2} = \frac{1}{9^{2}}
\]
Thus, the expression becomes:
\[
\frac{2^{3}}{9^{2}}
\]
Therefore, the equivalent expression to \( \frac{\left(2^{-3} \cdot 9^{3}\right)^{-4}}{2^{9} \cdot 9^{-10}} \) with only positive exponents is:
\[
\frac{2^{3}}{9^{2}}
\]
So the answer is:
\[
\frac{2^{3}}{9^{2}}
\]
Quick Answer
\[
\frac{2^{3}}{9^{2}}
\]
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