Higgins Garrett
04/16/2023 · Middle School
23) Which of the following processes is easy to occur? a) \( \mathrm{V}_{2} \mathrm{O}_{5} \rightarrow \mathrm{V}_{2} \mathrm{O}_{3} \) b) \( \mathrm{KMnO}_{4} \rightarrow \mathrm{Mn}_{2} \mathrm{O}_{3} \) c) \( \mathrm{TiCl}_{2} \rightarrow \mathrm{TiCl}_{4} \) d) \( \mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow \mathrm{FeSO}_{4} \)
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Step-by-step Solution
To determine which of the given processes is easy to occur, we need to consider the oxidation states and the stability of the compounds involved in each reaction.
a) \( \mathrm{V}_{2} \mathrm{O}_{5} \rightarrow \mathrm{V}_{2} \mathrm{O}_{3} \): This reaction involves the reduction of vanadium from a +5 oxidation state in \( \mathrm{V}_{2} \mathrm{O}_{5} \) to a +3 oxidation state in \( \mathrm{V}_{2} \mathrm{O}_{3} \). This is a common reduction process and can occur under suitable conditions.
b) \( \mathrm{KMnO}_{4} \rightarrow \mathrm{Mn}_{2} \mathrm{O}_{3} \): This reaction involves the reduction of manganese from a +7 oxidation state in \( \mathrm{KMnO}_{4} \) to a +3 oxidation state in \( \mathrm{Mn}_{2} \mathrm{O}_{3} \). This is a significant reduction and typically requires strong reducing agents or specific conditions.
c) \( \mathrm{TiCl}_{2} \rightarrow \mathrm{TiCl}_{4} \): This reaction involves the oxidation of titanium from a +2 oxidation state in \( \mathrm{TiCl}_{2} \) to a +4 oxidation state in \( \mathrm{TiCl}_{4} \). This is an oxidation process that can occur readily, especially in the presence of chlorine gas.
d) \( \mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow \mathrm{FeSO}_{4} \): This reaction involves the conversion of iron(III) oxide to iron(II) sulfate. This is not a straightforward reaction and typically requires specific conditions, such as the presence of sulfuric acid.
Considering the above analyses, the easiest process to occur among the options is:
**c) \( \mathrm{TiCl}_{2} \rightarrow \mathrm{TiCl}_{4} \)**
This reaction is relatively straightforward and can occur under standard conditions with the presence of chlorine.
Quick Answer
The easiest process to occur is c) \( \mathrm{TiCl}_{2} \rightarrow \mathrm{TiCl}_{4} \).
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