Watson Marshall
08/22/2023 · Senior High School

4. Evaluate the expression \( \frac{x+2 x+3 x+4 x+5 x}{x} \) for each \( x \) value given. \( \begin{array}{llll}\text { a. } 1 & \text { b. } 2 & \text { c. } 3 & \text { d. }-3 \\ \text { e. }-11 & \text { f. } \frac{1}{2} & \text { g. } 197 & \end{array} \)

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To evaluate the expression \( \frac{x + 2x + 3x + 4x + 5x}{x} \), we first simplify the numerator: \[ x + 2x + 3x + 4x + 5x = (1 + 2 + 3 + 4 + 5)x = 15x \] Now, substituting this back into the expression gives: \[ \frac{15x}{x} \] Assuming \( x \neq 0 \), we can simplify this to: \[ 15 \] Now, we will evaluate the expression for each given value of \( x \): - **a. \( x = 1 \)**: \[ 15 \] - **b. \( x = 2 \)**: \[ 15 \] - **c. \( x = 3 \)**: \[ 15 \] - **d. \( x = -3 \)**: \[ 15 \] - **e. \( x = -11 \)**: \[ 15 \] - **f. \( x = \frac{1}{2} \)**: \[ 15 \] - **g. \( x = 197 \)**: \[ 15 \] In conclusion, for all the given values of \( x \) (except \( x = 0 \), which is not included in the list), the expression evaluates to: \[ \boxed{15} \]

Quick Answer

For all given \( x \) values, the expression evaluates to 15.
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