Johnson Robbins
11/18/2023 · High School
(c) the cylinder is open on top and the dimensions are radius \( =3 \mathrm{~cm} \) and height \( =5 \mathrm{~cm} \)
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Step-by-step Solution
To find the surface area and volume of an open-top cylinder with a radius of \(3 \, \text{cm}\) and a height of \(5 \, \text{cm}\), we can use the following formulas:
### Volume of the Cylinder
The volume \( V \) of a cylinder is given by the formula:
\[
V = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.
Substituting the given values:
\[
V = \pi (3 \, \text{cm})^2 (5 \, \text{cm}) = \pi (9 \, \text{cm}^2)(5 \, \text{cm}) = 45\pi \, \text{cm}^3
\]
### Surface Area of the Open-Top Cylinder
The surface area \( A \) of an open-top cylinder consists of the area of the base and the lateral surface area. The formula is:
\[
A = \text{Base Area} + \text{Lateral Surface Area}
\]
1. **Base Area**: The area of the base is given by:
\[
\text{Base Area} = \pi r^2 = \pi (3 \, \text{cm})^2 = 9\pi \, \text{cm}^2
\]
2. **Lateral Surface Area**: The lateral surface area is given by:
\[
\text{Lateral Surface Area} = 2\pi rh = 2\pi (3 \, \text{cm})(5 \, \text{cm}) = 30\pi \, \text{cm}^2
\]
Now, adding these two areas together:
\[
A = 9\pi \, \text{cm}^2 + 30\pi \, \text{cm}^2 = 39\pi \, \text{cm}^2
\]
### Summary
- **Volume**: \( 45\pi \, \text{cm}^3 \) (approximately \( 141.37 \, \text{cm}^3 \))
- **Surface Area**: \( 39\pi \, \text{cm}^2 \) (approximately \( 122.52 \, \text{cm}^2 \))
Quick Answer
The volume of the open-top cylinder is \( 45\pi \, \text{cm}^3 \) and the surface area is \( 39\pi \, \text{cm}^2 \).
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