A lift with a mass of 2000 kg is hoisted from a mine shaft. Calculate the work done if the shaft is \( 1,2 \mathrm{~km} \) deep.

To calculate the work done in lifting the lift from the mine shaft, we need to consider the force required to lift the lift and the distance over which this force is applied. Given: - Mass of the lift = 2000 kg - Depth of the shaft = 1.2 km The force required to lift the lift is equal to the weight of the lift, which is given by: \[ F = m \times g \] where: - \( m \) is the mass of the lift - \( g \) is the acceleration due to gravity (approximately 9.81 m/s^2) The work done in lifting the lift is given by: \[ W = F \times d \] where: - \( F \) is the force required to lift the lift - \( d \) is the distance over which the force is applied Let's calculate the work done. Calculate the value by following steps: - step0: Calculate: \(2000\times 9.81\times 1200\) - step1: Multiply the terms: \(19620\times 1200\) - step2: Multiply the numbers: \(23544000\) The work done in lifting the lift from the mine shaft is approximately 23544000 Joules or 2.3544 x 10^7 Joules.