$$ \begin{array}{ll} ext { (3) } 166 & ext { (4) } 164 \ ext { The number which exceeds } 16 \% ext { of itself by } 42 ext {, is }\end{array} $$

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$$ \begin{array}{ll}	ext { (3) } 166 & 	ext { (4) } 164 \ 	ext { The number which exceeds } 16 \% 	ext { of itself by } 42 	ext {, is }\end{array} $$

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The number is 50. Let the number be $$ x $$. According to the problem, the number exceeds 16% of itself by 42. We can express this mathematically as: $$ x - 0.16x = 42 $$ Simplifying the left side, we have: $$ 0.84x = 42 $$ To find $$ x $$, we divide both sides by 0.84: $$ x = \frac{42}{0.84} $$ Calculating the right side: $$ x = 50 $$ Thus, the number which exceeds 16% of itself by 42 is $$ \boxed{50} $$.

\( \begin{array}{ll}\text { (3) } 166 & \text { (4) } 164 \\ \text { The number which exceeds } 16 \% \text { of itself by } 42 \text {, is }\end{array} \)

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\( \begin{array}{ll}\text { (3) } 166 & \text { (4) } 164 \\ \text { The number which exceeds } 16 \% \text { of itself by } 42 \text {, is }\end{array} \)

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