Dickson Reyes
11/21/2023 · Senior High School
d the following matrices where \( \mathrm{A}=\left[\begin{array}{rr}6 & -7 \\ -4 & 6 \\ -1 & 4\end{array}\right] \) and \( \mathrm{B}=\left[\begin{array}{rr}-9 & 8 \\ 3 & 0 \\ -3 & 8\end{array}\right] \) \( \begin{array}{lll}\text { a. } \mathrm{A}+\mathrm{B} & \text { b. } \mathrm{A}-\mathrm{B} & \text { d. }-3 A-9 B\end{array} \) A. \( \mathrm{A}+\mathrm{B}=\square \) (Simplify your answer.) B. This matrix operation is not possible:
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Step-by-step Solution
To perform the matrix operations, we first need to check the dimensions of the matrices \( \mathrm{A} \) and \( \mathrm{B} \).
Matrix \( \mathrm{A} \) is a \( 3 \times 2 \) matrix:
\[
\mathrm{A} = \begin{bmatrix}
6 & -7 \\
-4 & 6 \\
-1 & 4
\end{bmatrix}
\]
Matrix \( \mathrm{B} \) is also a \( 3 \times 2 \) matrix:
\[
\mathrm{B} = \begin{bmatrix}
-9 & 8 \\
3 & 0 \\
-3 & 8
\end{bmatrix}
\]
Since both matrices have the same dimensions, we can perform addition and subtraction.
### a. \( \mathrm{A} + \mathrm{B} \)
To add the matrices, we add the corresponding elements:
\[
\mathrm{A} + \mathrm{B} = \begin{bmatrix}
6 + (-9) & -7 + 8 \\
-4 + 3 & 6 + 0 \\
-1 + (-3) & 4 + 8
\end{bmatrix}
\]
Calculating each element:
\[
= \begin{bmatrix}
-3 & 1 \\
-1 & 6 \\
-4 & 12
\end{bmatrix}
\]
So,
\[
\mathrm{A} + \mathrm{B} = \begin{bmatrix}
-3 & 1 \\
-1 & 6 \\
-4 & 12
\end{bmatrix}
\]
### b. \( \mathrm{A} - \mathrm{B} \)
To subtract the matrices, we subtract the corresponding elements:
\[
\mathrm{A} - \mathrm{B} = \begin{bmatrix}
6 - (-9) & -7 - 8 \\
-4 - 3 & 6 - 0 \\
-1 - (-3) & 4 - 8
\end{bmatrix}
\]
Calculating each element:
\[
= \begin{bmatrix}
15 & -15 \\
-7 & 6 \\
2 & -4
\end{bmatrix}
\]
So,
\[
\mathrm{A} - \mathrm{B} = \begin{bmatrix}
15 & -15 \\
-7 & 6 \\
2 & -4
\end{bmatrix}
\]
### d. \( -3\mathrm{A} - 9\mathrm{B} \)
First, we calculate \( -3\mathrm{A} \) and \( -9\mathrm{B} \):
\[
-3\mathrm{A} = -3 \begin{bmatrix}
6 & -7 \\
-4 & 6 \\
-1 & 4
\end{bmatrix} = \begin{bmatrix}
-18 & 21 \\
12 & -18 \\
3 & -12
\end{bmatrix}
\]
\[
-9\mathrm{B} = -9 \begin{bmatrix}
-9 & 8 \\
3 & 0 \\
-3 & 8
\end{bmatrix} = \begin{bmatrix}
81 & -72 \\
-27 & 0 \\
27 & -72
\end{bmatrix}
\]
Now, we add these two results:
\[
-3\mathrm{A} - 9\mathrm{B} = \begin{bmatrix}
-18 & 21 \\
12 & -18 \\
3 & -12
\end{bmatrix} + \begin{bmatrix}
81 & -72 \\
-27 & 0 \\
27 & -72
\end{bmatrix}
\]
Calculating each element:
\[
= \begin{bmatrix}
-18 + 81 & 21 - 72 \\
12 - 27 & -18 + 0 \\
3 + 27 & -12 - 72
\end{bmatrix}
\]
\[
= \begin{bmatrix}
63 & -51 \\
-15 & -18 \\
30 & -84
\end{bmatrix}
\]
So,
\[
-3\mathrm{A} - 9\mathrm{B} = \begin{bmatrix}
63 & -51 \\
-15 & -18 \\
30 & -84
\end{bmatrix}
\]
### Summary of Results:
- \( \mathrm{A} + \mathrm{B} = \begin{bmatrix} -3 & 1 \\ -1 & 6 \\ -4 & 12 \end{bmatrix} \)
- \( \mathrm{A} - \mathrm{B} = \begin{bmatrix} 15 & -15 \\ -7 & 6 \\ 2 & -4 \end{bmatrix} \)
- \( -3\mathrm{A} - 9\mathrm{B} = \begin{bmatrix} 63 & -51 \\ -15 & -18 \\ 30 & -84 \end{bmatrix} \)
Quick Answer
A. \( \mathrm{A}+\mathrm{B}=\begin{bmatrix} -3 & 1 \\ -1 & 6 \\ -4 & 12 \end{bmatrix} \)
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