Moreno Murray
06/27/2024 · Junior High School

\( P=\{x \mid 10

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Step-by-step Solution

Mari kita tentukan himpunan \( P \) dan \( Q \) terlebih dahulu. 1. **Himpunan \( P \)**: \[ P = \{x \mid 10 < x < 25, x \in \text{bilangan bulat}\} \] Bilangan bulat yang memenuhi syarat tersebut adalah: \[ P = \{11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24\} \] 2. **Himpunan \( Q \)**: \[ Q = \{x \mid 5 \leq x \leq 21, x \in \text{bilangan prima}\} \] Bilangan prima yang memenuhi syarat tersebut adalah: \[ Q = \{5, 7, 11, 13, 17, 19, 23\} \] 3. **Menghitung \( P - Q \)**: Kita perlu menghapus elemen-elemen yang ada di \( Q \) dari \( P \): - Dari \( P \), kita lihat elemen-elemen yang juga ada di \( Q \): - \( 11 \) ada di \( Q \) - \( 13 \) ada di \( Q \) - \( 17 \) ada di \( Q \) - \( 19 \) ada di \( Q \) Jadi, kita hapus \( 11, 13, 17, 19 \) dari \( P \): \[ P - Q = \{12, 14, 15, 16, 18, 20, 21, 22, 23, 24\} - \{11, 13, 17, 19\} \] Hasilnya adalah: \[ P - Q = \{12, 14, 15, 16, 18, 20, 21, 22, 23, 24\} \] 4. **Mencocokkan dengan pilihan jawaban**: Dari pilihan yang ada, kita lihat: - A \( \{12,14,15,16,18,20,21,22,24\} \) (salah, tidak ada 23) - B \( \{12,14,15,16,18,20,21,22,23,24\} \) (benar) - C \( \{12,14,15,16,18,19,20,21,22,23,24\} \) (salah, ada 19) - D \( \{12,14,15,16,20,21,22,24\} \) (salah, tidak ada 18 dan 23) - E \( \{12,14,15,16,21,22,24\} \) (salah, tidak ada 18 dan 20) Jadi, hasil dari \( P - Q \) adalah: \[ \boxed{B} \]

Quick Answer

Hasil dari \( P - Q \) adalah \( \{12,14,15,16,18,20,21,22,23,24\} \). Jadi, pilihan yang benar adalah B.
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