Salinas Ramirez
09/24/2024 · Middle School
Find the real zeros, if any, of the quadratic function using the quadratic formula. What are the \( x \)-intercepts, if any, of the graph of the function? \( f(x)=x^{2}+4 x+1 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) A. The zeros and the x-intercepts are the same. They are B. The zeros and the x-intercepts are different. The zeros are C. There is no real zero solution and no \( x \)-intercepts are
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To find the real zeros of the quadratic function \( f(x) = x^2 + 4x + 1 \), we can use the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In this case, the coefficients are:
- \( a = 1 \)
- \( b = 4 \)
- \( c = 1 \)
Now, we can calculate the discriminant \( b^2 - 4ac \):
\[
b^2 - 4ac = 4^2 - 4 \cdot 1 \cdot 1 = 16 - 4 = 12
\]
Since the discriminant is positive (\( 12 > 0 \)), there are two distinct real zeros.
Now we can substitute the values into the quadratic formula:
\[
x = \frac{-4 \pm \sqrt{12}}{2 \cdot 1}
\]
We can simplify \( \sqrt{12} \):
\[
\sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3}
\]
Now substituting back into the formula:
\[
x = \frac{-4 \pm 2\sqrt{3}}{2}
\]
This simplifies to:
\[
x = \frac{-4}{2} \pm \frac{2\sqrt{3}}{2} = -2 \pm \sqrt{3}
\]
Thus, the two real zeros are:
\[
x = -2 + \sqrt{3} \quad \text{and} \quad x = -2 - \sqrt{3}
\]
Now, we can summarize the results:
A. The zeros and the x-intercepts are the same. They are:
\[
-2 + \sqrt{3}, -2 - \sqrt{3}
\]
So the correct choice is A, and the zeros (and x-intercepts) are:
\[
-2 + \sqrt{3}, -2 - \sqrt{3}
\]
Quick Answer
The zeros (and x-intercepts) are \( -2 + \sqrt{3} \) and \( -2 - \sqrt{3} \).
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit