Mullins Love
04/10/2023 · Senior High School
4. Choose the correct graph of the function \( y=-\frac{1}{2} \sqrt{x-2}-3 \)
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Step-by-step Solution
To help you choose the correct graph of the function \( y=-\frac{1}{2} \sqrt{x-2}-3 \), let's analyze the function step by step:
1. **Domain**: The function contains a square root, which means the expression inside the square root must be non-negative. Therefore, \( x-2 \geq 0 \), which implies \( x \geq 2 \). The domain of the function is \( [2, \infty) \).
2. **Asymptote**: The function has a vertical asymptote at \( x=2 \) because the square root term becomes undefined when \( x \) is less than 2.
3. **Y-Intercept**: To find the y-intercept, set \( x=0 \). However, since the domain is \( [2, \infty) \), there is no y-intercept.
4. **X-Intercept**: To find the x-intercept, set \( y=0 \) and solve for \( x \):
\[ 0 = -\frac{1}{2} \sqrt{x-2} - 3 \]
\[ \frac{1}{2} \sqrt{x-2} = -3 \]
\[ \sqrt{x-2} = -6 \]
Since the square root of a real number cannot be negative, there is no x-intercept.
5. **Behavior**: The function is decreasing because the coefficient of the square root is negative, and the function is shifted down by 3 units.
6. **Graph**: Based on the above analysis, the graph should have the following characteristics:
- A vertical asymptote at \( x=2 \)
- No y-intercept
- No x-intercept
- Decreasing as \( x \) increases
- Shifted down by 3 units
Now, let's look at the provided graphs and choose the one that matches these characteristics. Since I cannot see the graphs, I cannot directly tell you which one is correct. However, you can use the above analysis to identify the correct graph.
Quick Answer
The graph should have a vertical asymptote at \( x=2 \), no y-intercept, no x-intercept, be decreasing as \( x \) increases, and shifted down by 3 units. Use this analysis to identify the correct graph.
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