Joseph Newton
05/19/2023 · Elementary School
11) El producto entre 25 y 4 , disminuido 4 unidades R: 12) Si \( n-26=50 \), entonces \( n=76 \) 13) \( (9 \times 3)+(80 \div 2)= \)
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Vamos a resolver cada uno de los problemas que has planteado:
11) El producto entre 25 y 4, disminuido 4 unidades:
\[
25 \times 4 = 100
\]
Ahora, disminuimos 4 unidades:
\[
100 - 4 = 96
\]
Por lo tanto, la respuesta es **96**.
12) Si \( n - 26 = 50 \), entonces para encontrar \( n \) sumamos 26 a ambos lados de la ecuación:
\[
n = 50 + 26 = 76
\]
La afirmación es correcta, así que \( n = 76 \).
13) Calculamos \( (9 \times 3) + (80 \div 2) \):
Primero, calculamos \( 9 \times 3 \):
\[
9 \times 3 = 27
\]
Luego, calculamos \( 80 \div 2 \):
\[
80 \div 2 = 40
\]
Ahora sumamos ambos resultados:
\[
27 + 40 = 67
\]
Por lo tanto, la respuesta es **67**.
Resumiendo:
- 11) 96
- 12) \( n = 76 \)
- 13) 67
Quick Answer
11) 96
12) \( n = 76 \)
13) 67
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