$$ \left\{\begin{array}{l}y=2x \f(x)=-2x\end{array} ight. $$

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$$ \left\{\begin{array}{l}y=2x \f(x)=-2x\end{array}ight. $$

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The intersection point is $$ (0, 0) $$. You have provided two equations: 1. $$ y = 2x $$ 2. $$ f(x) = -2x $$ If you are looking to find the intersection of these two equations, you can set them equal to each other since $$ y $$ can be represented as $$ f(x) $$: $$ 2x = -2x $$ Now, solve for $$ x $$: $$ 2x + 2x = 0 \ 4x = 0 \ x = 0 $$ Now, substitute $$ x = 0 $$ back into either equation to find $$ y $$: Using $$ y = 2x $$: $$ y = 2(0) = 0 $$ So, the intersection point is $$ (0, 0) $$. If you have a different question or need further analysis, please let me know!

\( \left\{\begin{array}{l}y=2x \\f(x)=-2x\end{array}\right. \)

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\( \left\{\begin{array}{l}y=2x \\f(x)=-2x\end{array}\right. \)

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