QUESTION 8 The sum of $$ x^{-1} $$ and $$ y^{-1} $$ in the most simplified form is $$ \left.\begin{array}{ll} ext { A. } \frac{1}{x y} & ext { B. } \frac{x y+1}{x y} \ ext { C. } \frac{y+x}{x y} & ext { D. } \frac{x y-1}{x y}\end{array} ight\} $$

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QUESTION 8 The sum of $$ x^{-1} $$ and $$ y^{-1} $$ in the most simplified form is $$ \left.\begin{array}{ll}	ext { A. } \frac{1}{x y} & 	ext { B. } \frac{x y+1}{x y} \ 	ext { C. } \frac{y+x}{x y} & 	ext { D. } \frac{x y-1}{x y}\end{array}ight\} $$

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The sum of $$ x^{-1} $$ and $$ y^{-1} $$ is $$ \frac{y + x}{xy} $$. Therefore, the correct answer is C. To find the sum of $$ x^{-1} $$ and $$ y^{-1} $$, we start by rewriting these terms: $$ x^{-1} = \frac{1}{x} \quad \text{and} \quad y^{-1} = \frac{1}{y} $$ Now, we can add these two fractions: $$ x^{-1} + y^{-1} = \frac{1}{x} + \frac{1}{y} $$ To add these fractions, we need a common denominator, which is $$ xy $$: $$ \frac{1}{x} + \frac{1}{y} = \frac{y}{xy} + \frac{x}{xy} = \frac{y + x}{xy} $$ Thus, the sum of $$ x^{-1} $$ and $$ y^{-1} $$ in its most simplified form is: $$ \frac{x + y}{xy} $$ Looking at the answer choices provided: - A. $$ \frac{1}{xy} $$ - B. $$ \frac{xy + 1}{xy} $$ - C. $$ \frac{y + x}{xy} $$ - D. $$ \frac{xy - 1}{xy} $$ The correct answer is: $$ \text{C. } \frac{y + x}{xy} $$

QUESTION 8 The sum of \( x^{-1} \) and \( y^{-1} \) in the most simplified form is \( \left.\begin{array}{ll}\text { A. } \frac{1}{x y} & \text { B. } \frac{x y+1}{x y} \\ \text { C. } \frac{y+x}{x y} & \text { D. } \frac{x y-1}{x y}\end{array}\right\} \)

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QUESTION 8 The sum of \( x^{-1} \) and \( y^{-1} \) in the most simplified form is \( \left.\begin{array}{ll}\text { A. } \frac{1}{x y} & \text { B. } \frac{x y+1}{x y} \\ \text { C. } \frac{y+x}{x y} & \text { D. } \frac{x y-1}{x y}\end{array}\right\} \)

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