Collins Weston
12/21/2023 · Primary School
21 \( \sqrt{1-\frac{7}{8}}-\frac{8}{9} \cdot\left(1-\frac{1}{4}\right)^{3} \) \( 1-7=\sqrt{6}=8-8 \)
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Tutor-Verified Answer
Step-by-step Solution
Let's simplify the expression step by step.
The expression is:
\[
21 \sqrt{1 - \frac{7}{8}} - \frac{8}{9} \cdot \left(1 - \frac{1}{4}\right)^{3}
\]
### Step 1: Simplify \( \sqrt{1 - \frac{7}{8}} \)
First, calculate \( 1 - \frac{7}{8} \):
\[
1 - \frac{7}{8} = \frac{8}{8} - \frac{7}{8} = \frac{1}{8}
\]
Now, take the square root:
\[
\sqrt{1 - \frac{7}{8}} = \sqrt{\frac{1}{8}} = \frac{1}{\sqrt{8}} = \frac{1}{2\sqrt{2}} = \frac{\sqrt{2}}{4}
\]
### Step 2: Calculate \( 21 \sqrt{1 - \frac{7}{8}} \)
Now, multiply by 21:
\[
21 \sqrt{1 - \frac{7}{8}} = 21 \cdot \frac{\sqrt{2}}{4} = \frac{21\sqrt{2}}{4}
\]
### Step 3: Simplify \( \left(1 - \frac{1}{4}\right)^{3} \)
Calculate \( 1 - \frac{1}{4} \):
\[
1 - \frac{1}{4} = \frac{3}{4}
\]
Now, raise it to the power of 3:
\[
\left(\frac{3}{4}\right)^{3} = \frac{27}{64}
\]
### Step 4: Calculate \( \frac{8}{9} \cdot \left(1 - \frac{1}{4}\right)^{3} \)
Now, multiply by \( \frac{8}{9} \):
\[
\frac{8}{9} \cdot \frac{27}{64} = \frac{8 \cdot 27}{9 \cdot 64} = \frac{216}{576}
\]
Now simplify \( \frac{216}{576} \):
\[
\frac{216 \div 72}{576 \div 72} = \frac{3}{8}
\]
### Step 5: Combine the results
Now we have:
\[
21 \sqrt{1 - \frac{7}{8}} - \frac{8}{9} \cdot \left(1 - \frac{1}{4}\right)^{3} = \frac{21\sqrt{2}}{4} - \frac{3}{8}
\]
To combine these fractions, we need a common denominator. The common denominator of 4 and 8 is 8.
Convert \( \frac{21\sqrt{2}}{4} \) to have a denominator of 8:
\[
\frac{21\sqrt{2}}{4} = \frac{21\sqrt{2} \cdot 2}{4 \cdot 2} = \frac{42\sqrt{2}}{8}
\]
Now we can combine:
\[
\frac{42\sqrt{2}}{8} - \frac{3}{8} = \frac{42\sqrt{2} - 3}{8}
\]
### Final Result
Thus, the final simplified expression is:
\[
\frac{42\sqrt{2} - 3}{8}
\]
Quick Answer
\(\frac{42\sqrt{2} - 3}{8}\)
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