Cummings Mcfarlane
12/13/2023 · Junior High School
The equation of a circle is given in standard form. Complete parts a through \( c \) to follow the step by step process to sketch the \( (x+1)^{2}+(y-4)^{2}=29 \) a) Determine the center and radius of the circle. The center of the circle is (Type an ordered pair.)
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Step-by-step Solution
To determine the center and radius of the circle given by the equation \((x+1)^{2}+(y-4)^{2}=29\), we can compare it to the standard form of a circle's equation, which is:
\[
(x - h)^{2} + (y - k)^{2} = r^{2}
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
From the given equation \((x+1)^{2}+(y-4)^{2}=29\):
1. The term \((x + 1)^{2}\) can be rewritten as \((x - (-1))^{2}\), indicating that \(h = -1\).
2. The term \((y - 4)^{2}\) indicates that \(k = 4\).
3. The right side of the equation, \(29\), represents \(r^{2}\). Therefore, to find the radius \(r\), we take the square root of \(29\):
\[
r = \sqrt{29}
\]
Now we can summarize the center and radius:
- The center of the circle is \((-1, 4)\).
- The radius of the circle is \(\sqrt{29}\).
Thus, the answer for part a is:
The center of the circle is \((-1, 4)\).
Quick Answer
The center of the circle is \((-1, 4)\).
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