Herrera Daniels
08/22/2024 · High School
\( 9.8 \times \frac{1}{2}+0.5 \times \mathrm{V}_{\mathrm{B}}^{2} \) \( =0.8 \times \mathrm{V}_{\mathrm{B}}^{2} \) (subtract from both sides)
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Step-by-step Solution
To solve the given equation, we will first subtract \(0.8 \times \mathrm{V}_{\mathrm{B}}^{2}\) from both sides of the equation.
Given equation: \( 9.8 \times \frac{1}{2} + 0.5 \times \mathrm{V}_{\mathrm{B}}^{2} = 0.8 \times \mathrm{V}_{\mathrm{B}}^{2} \)
Subtracting \(0.8 \times \mathrm{V}_{\mathrm{B}}^{2}\) from both sides:
\( 9.8 \times \frac{1}{2} + 0.5 \times \mathrm{V}_{\mathrm{B}}^{2} - 0.8 \times \mathrm{V}_{\mathrm{B}}^{2} = 0.8 \times \mathrm{V}_{\mathrm{B}}^{2} - 0.8 \times \mathrm{V}_{\mathrm{B}}^{2} \)
Simplifying the equation:
\( 4.9 + 0.5 \times \mathrm{V}_{\mathrm{B}}^{2} - 0.8 \times \mathrm{V}_{\mathrm{B}}^{2} = 0 \)
\( 4.9 - 0.3 \times \mathrm{V}_{\mathrm{B}}^{2} = 0 \)
Now, we have the simplified equation \( 4.9 - 0.3 \times \mathrm{V}_{\mathrm{B}}^{2} = 0 \).
Quick Answer
The simplified equation is \( 4.9 - 0.3 \times \mathrm{V}_{\mathrm{B}}^{2} = 0 \).
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