Gordon Schofield
09/23/2023 · Middle School

Encuentra la suma de la serie geométrica \( +1.2+1.2^{2}+1.2^{3}+\ldots+1.2^{74} \)

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La serie que se presenta es una serie geométrica de la forma: \[ S = a + ar + ar^2 + ar^3 + \ldots + ar^n \] donde: - \( a \) es el primer término de la serie, - \( r \) es la razón de la serie, - \( n \) es el número de términos menos uno. En este caso, tenemos: - \( a = 1.2 \) - \( r = 1.2 \) - \( n = 74 \) (ya que el último término es \( 1.2^{74} \)) La fórmula para la suma de una serie geométrica es: \[ S_n = a \frac{r^{n+1} - 1}{r - 1} \] Sustituyendo los valores: \[ S_{74} = 1.2 \frac{(1.2)^{74+1} - 1}{1.2 - 1} \] Calculamos \( 1.2 - 1 \): \[ 1.2 - 1 = 0.2 \] Ahora sustituimos en la fórmula: \[ S_{74} = 1.2 \frac{(1.2)^{75} - 1}{0.2} \] Simplificamos: \[ S_{74} = 1.2 \cdot 5 \cdot ((1.2)^{75} - 1) \] \[ S_{74} = 6 \cdot ((1.2)^{75} - 1) \] Ahora, necesitamos calcular \( (1.2)^{75} \). Usando una calculadora o software, encontramos que: \[ (1.2)^{75} \approx 103.671 \] Sustituyendo este valor en la suma: \[ S_{74} = 6 \cdot (103.671 - 1) \] \[ S_{74} = 6 \cdot 102.671 \] \[ S_{74} \approx 616.026 \] Por lo tanto, la suma de la serie geométrica es aproximadamente: \[ \boxed{616.026} \]

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La suma de la serie geométrica es aproximadamente 616.026.
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