Fowler Perkins
02/25/2024 · High School
\( \left. \begin{array} { l } { y a y b \quad a = x + b \quad b = x } \\ { y ( x + b ) c } \end{array} \right. \)
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Step-by-step Solution
It seems like you have provided a mathematical expression or a system of equations, but the formatting is a bit unclear. Let's break it down step by step.
From what you've written, it looks like you have:
1. \( a = x + b \)
2. \( b = x \)
3. \( y a y b \)
4. \( y (x + b) c \)
Let's analyze these equations:
1. From \( b = x \), we can substitute \( b \) into the first equation:
\[
a = x + b = x + x = 2x
\]
2. Now we have:
- \( a = 2x \)
- \( b = x \)
3. The expression \( y a y b \) can be interpreted as \( y \cdot a \cdot y \cdot b \):
\[
y a y b = y \cdot (2x) \cdot y \cdot x = 2xy^2
\]
4. The expression \( y (x + b) c \) can be simplified using \( b = x \):
\[
y (x + b) c = y (x + x) c = y (2x) c = 2xyc
\]
So, summarizing the results:
- \( a = 2x \)
- \( b = x \)
- \( y a y b = 2xy^2 \)
- \( y (x + b) c = 2xyc \)
If you have a specific question or need further assistance with this expression, please let me know!
Quick Answer
- \( a = 2x \)
- \( b = x \)
- \( y a y b = 2xy^2 \)
- \( y (x + b) c = 2xyc \)
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