Fowler Perkins
02/25/2024 · High School

\( \left. \begin{array} { l } { y a y b \quad a = x + b \quad b = x } \\ { y ( x + b ) c } \end{array} \right. \)

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It seems like you have provided a mathematical expression or a system of equations, but the formatting is a bit unclear. Let's break it down step by step. From what you've written, it looks like you have: 1. \( a = x + b \) 2. \( b = x \) 3. \( y a y b \) 4. \( y (x + b) c \) Let's analyze these equations: 1. From \( b = x \), we can substitute \( b \) into the first equation: \[ a = x + b = x + x = 2x \] 2. Now we have: - \( a = 2x \) - \( b = x \) 3. The expression \( y a y b \) can be interpreted as \( y \cdot a \cdot y \cdot b \): \[ y a y b = y \cdot (2x) \cdot y \cdot x = 2xy^2 \] 4. The expression \( y (x + b) c \) can be simplified using \( b = x \): \[ y (x + b) c = y (x + x) c = y (2x) c = 2xyc \] So, summarizing the results: - \( a = 2x \) - \( b = x \) - \( y a y b = 2xy^2 \) - \( y (x + b) c = 2xyc \) If you have a specific question or need further assistance with this expression, please let me know!

Quick Answer

- \( a = 2x \) - \( b = x \) - \( y a y b = 2xy^2 \) - \( y (x + b) c = 2xyc \)
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