\( f _ { - 2 } ^ { - 2 } ( x , y ) / y = a x ^ { 2 } b x + c , a \in R , b \in R , C \in R \wedge a \neq 0 \} \)

The expression you've provided seems to involve a function notation that is not standard, particularly with the use of \( f_{-2}^{-2}(x, y) \). It appears you might be trying to express a relationship involving a function of two variables \( x \) and \( y \), and then equate it to a quadratic expression in \( x \). To clarify, let's break down the components: 1. **Function Notation**: The notation \( f_{-2}^{-2}(x, y) \) is not standard. If you meant to denote a specific function or transformation, please clarify what \( f_{-2}^{-2} \) represents. 2. **Equation**: The equation \( \frac{f_{-2}^{-2}(x, y)}{y} = ax^2 + bx + c \) suggests that you are defining a relationship where the left-hand side is a function of \( x \) and \( y \) divided by \( y \), and the right-hand side is a quadratic polynomial in \( x \). 3. **Parameters**: The parameters \( a, b, c \) are real numbers, with the condition that \( a \neq 0 \), indicating that the quadratic term is present. If you are looking to solve for \( f_{-2}^{-2}(x, y) \) in terms of \( x \) and \( y \), you can rearrange the equation: \[ f_{-2}^{-2}(x, y) = y(ax^2 + bx + c) \] This gives you a function \( f_{-2}^{-2}(x, y) \) that is dependent on both \( x \) and \( y \). If you have a specific context or additional details about the function \( f_{-2}^{-2} \) or the problem you are trying to solve, please provide that information for a more tailored response!