1) ix \( ^{2}, \mathrm{~F}(0,-16) \) and \( G(-8,-4) \) are the endpoints of a line segment. What is the midpoint \( M \) that line segment? 1) \( M=( \) Write the coordinates as decimals or integers. Submit

To find the midpoint \( M \) of a line segment with endpoints \( F(0, -16) \) and \( G(-8, -4) \), you can use the midpoint formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] where \( (x_1, y_1) \) are the coordinates of point \( F \) and \( (x_2, y_2) \) are the coordinates of point \( G \). Substituting the coordinates of points \( F \) and \( G \): - \( F(0, -16) \) gives \( x_1 = 0 \) and \( y_1 = -16 \) - \( G(-8, -4) \) gives \( x_2 = -8 \) and \( y_2 = -4 \) Now, plug these values into the midpoint formula: \[ M = \left( \frac{0 + (-8)}{2}, \frac{-16 + (-4)}{2} \right) \] Calculating the x-coordinate: \[ \frac{0 - 8}{2} = \frac{-8}{2} = -4 \] Calculating the y-coordinate: \[ \frac{-16 - 4}{2} = \frac{-20}{2} = -10 \] Thus, the coordinates of the midpoint \( M \) are: \[ M = (-4, -10) \] So, the final answer is: \[ M = (-4, -10) \]