The domain of $$ f(x)=\frac{4 x-3}{4 x+3} $$ is (Type your answer in interval notation. Simplif)

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$$ (-\infty, -\frac{3}{4}) \cup (-\frac{3}{4}, \infty) $$ To find the domain of the function $$ f(x) = \frac{4x - 3}{4x + 3} $$, we need to determine where the function is defined. The function is a rational function, and it is undefined where the denominator is equal to zero. We set the denominator equal to zero and solve for $$ x $$: $$ 4x + 3 = 0 $$ Subtracting 3 from both sides gives: $$ 4x = -3 $$ Dividing both sides by 4 gives: $$ x = -\frac{3}{4} $$ Thus, the function $$ f(x) $$ is undefined at $$ x = -\frac{3}{4} $$. Therefore, the domain of $$ f(x) $$ includes all real numbers except $$ -\frac{3}{4} $$. In interval notation, the domain is: $$ (-\infty, -\frac{3}{4}) \cup (-\frac{3}{4}, \infty) $$

The domain of \( f(x)=\frac{4 x-3}{4 x+3} \) is (Type your answer in interval notation. Simplif)

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The domain of \( f(x)=\frac{4 x-3}{4 x+3} \) is (Type your answer in interval notation. Simplif)

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