Fill in the blanks so that the following statement is true. The fractions in the equation $$ \frac{x}{4}=3+\frac{x-4}{7} $$ can be eliminated by multiplying both sides by the 0 of 1 The fractions in the equation $$ \frac{x}{4}=3+\frac{x-4}{7} $$ can be eliminated by multiplying both sides by the $$ \square \frac{x}{4} $$ and $$ \frac{x-4}{7} $$, which is Thes of $$ \frac{x}{4} $$ and $$ \frac{x-4}{7} $$, which is

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The fractions can be eliminated by multiplying both sides by the least common multiple of the denominators, which is 28. To eliminate the fractions in the equation $$ \frac{x}{4} = 3 + \frac{x-4}{7} $$, we need to find a common multiple of the denominators, which are 4 and 7. The least common multiple (LCM) of 4 and 7 is 28. Therefore, we can multiply both sides of the equation by 28 to eliminate the fractions. So, the completed statement would be: The fractions in the equation $$ \frac{x}{4}=3+\frac{x-4}{7} $$ can be eliminated by multiplying both sides by the **least common multiple** of $$ \frac{x}{4} $$ and $$ \frac{x-4}{7} $$, which is **28**.

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